Attractive Force Potentials per unit Mass for Sun Solution

STEP 0: Pre-Calculation Summary
Formula Used
Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of point
Vs = (f*Msun)/rS/MX
This formula uses 4 Variables
Variables Used
Attractive Force Potentials for Sun - The Attractive Force Potentials for sun per unit mass of the Sun.
Universal Constant - Universal Constant in terms of Radius of the Earth and Acceleration of Gravity.
Mass of the Sun - (Measured in Kilogram) - Mass of the Sun [1.989 × 10^30 kg] about 333,000 times the mass of the Earth.
Distance of point - (Measured in Meter) - Distance of point located on the Surface of the Earth to the center of the Sun or the Moon.
STEP 1: Convert Input(s) to Base Unit
Universal Constant: 2 --> No Conversion Required
Mass of the Sun: 1.989E+30 Kilogram --> 1.989E+30 Kilogram No Conversion Required
Distance of point: 256 Kilometer --> 256000 Meter (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Vs = (f*Msun)/rS/MX --> (2*1.989E+30)/256000
Evaluating ... ...
Vs = 1.55390625E+25
STEP 3: Convert Result to Output's Unit
1.55390625E+25 --> No Conversion Required
FINAL ANSWER
1.55390625E+25 1.6E+25 <-- Attractive Force Potentials for Sun
(Calculation completed in 00.004 seconds)

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Coorg Institute of Technology (CIT), Coorg
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13 Attractive Force Potentials Calculators

Moon's Tide-generating attractive Force Potential
Go Attractive Force Potentials for Moon = Universal Constant*Mass of the Moon*((1/Distance of point)-(1/Distance from center of Earth to center of Moon)-([Earth-R]*cos(Angle made by the distance of point)/Distance from center of Earth to center of Moon^2))
Tide-generating attractive Force Potential for Sun
Go Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the distance of point)/Distance^2))
Mean radius of earth given attractive force potentials per unit mass for moon
Go Mean Radius of the Earth = sqrt((Attractive Force Potentials for Moon*Distance from center of Earth to center of Moon^3)/(Universal Constant*Mass of the Moon*Harmonic Polynomial Expansion Terms for Moon))
Attractive Force Potentials per unit Mass for Moon given Harmonic Polynomial Expansion
Go Attractive Force Potentials for Moon = (Universal Constant*Mass of the Moon)*(Mean Radius of the Earth^2/Distance from center of Earth to center of Moon^3)*Harmonic Polynomial Expansion Terms for Moon
Distance from center of earth to center of moon given attractive force potentials
Go Distance from center of Earth to center of Moon = (Mean Radius of the Earth^2*Universal Constant*[Moon-M]*Harmonic Polynomial Expansion Terms for Moon/Attractive Force Potentials for Moon)^(1/3)
Mean radius of earth given attractive force potentials per unit mass for Sun
Go Mean Radius of the Earth = sqrt((Attractive Force Potentials for Sun*Distance^3)/(Universal Constant*Mass of the Sun*Harmonic Polynomial Expansion Terms for Sun))
Attractive Force Potentials per unit Mass for Sun given Harmonic Polynomial Expansion
Go Attractive Force Potentials for Sun = Universal Constant*Mass of the Sun*(Mean Radius of the Earth^2/Distance^3)*Harmonic Polynomial Expansion Terms for Sun
Mass of Moon given attractive force potentials with harmonic polynomial expansion
Go Mass of the Moon = (Attractive Force Potentials for Moon*Distance from center of Earth to center of Moon^3)/([Earth-R]^2*Universal Constant*Harmonic Polynomial Expansion Terms for Moon)
Mass of Sun given attractive force potentials with harmonic polynomial expansion
Go Mass of the Sun = (Attractive Force Potentials for Sun*Distance^3)/([Earth-R]^2*Universal Constant*Harmonic Polynomial Expansion Terms for Sun)
Attractive Force Potentials per unit Mass for Moon
Go Attractive Force Potentials for Moon = (Universal Constant*Mass of the Moon)/Distance of point
Mass of Moon for Given Attractive Force Potentials
Go Mass of the Moon = (Attractive Force Potentials for Moon*Distance of point)/Universal Constant
Attractive Force Potentials per unit Mass for Sun
Go Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of point
Mass of Sun for Given Attractive Force Potentials
Go Mass of the Sun = (Attractive Force Potentials for Sun*Distance of point)/Universal Constant

Attractive Force Potentials per unit Mass for Sun Formula

Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of point
Vs = (f*Msun)/rS/MX

What do you mean by Tidal Force?

The Tidal Force is a gravitational effect that stretches a body along the line towards the center of mass of another body due to a gradient (difference in strength) in gravitational field from the other body; it is responsible for diverse phenomena, including tides, tidal locking, breaking apart of celestial bodies.

How to Calculate Attractive Force Potentials per unit Mass for Sun?

Attractive Force Potentials per unit Mass for Sun calculator uses Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of point to calculate the Attractive Force Potentials for Sun, The Attractive Force Potentials per unit Mass for Sun tends to make potential energy of system decrease. As atoms first begin to interact, attractive force is stronger than repulsive force and so potential energy of system decreases. Attractive Force Potentials for Sun is denoted by Vs symbol.

How to calculate Attractive Force Potentials per unit Mass for Sun using this online calculator? To use this online calculator for Attractive Force Potentials per unit Mass for Sun, enter Universal Constant (f), Mass of the Sun (Msun) & Distance of point (rS/MX) and hit the calculate button. Here is how the Attractive Force Potentials per unit Mass for Sun calculation can be explained with given input values -> 1.6E+25 = (2*1.989E+30)/256000.

FAQ

What is Attractive Force Potentials per unit Mass for Sun?
The Attractive Force Potentials per unit Mass for Sun tends to make potential energy of system decrease. As atoms first begin to interact, attractive force is stronger than repulsive force and so potential energy of system decreases and is represented as Vs = (f*Msun)/rS/MX or Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of point. Universal Constant in terms of Radius of the Earth and Acceleration of Gravity, Mass of the Sun [1.989 × 10^30 kg] about 333,000 times the mass of the Earth & Distance of point located on the Surface of the Earth to the center of the Sun or the Moon.
How to calculate Attractive Force Potentials per unit Mass for Sun?
The Attractive Force Potentials per unit Mass for Sun tends to make potential energy of system decrease. As atoms first begin to interact, attractive force is stronger than repulsive force and so potential energy of system decreases is calculated using Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of point. To calculate Attractive Force Potentials per unit Mass for Sun, you need Universal Constant (f), Mass of the Sun (Msun) & Distance of point (rS/MX). With our tool, you need to enter the respective value for Universal Constant, Mass of the Sun & Distance of point and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Attractive Force Potentials for Sun?
In this formula, Attractive Force Potentials for Sun uses Universal Constant, Mass of the Sun & Distance of point. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the distance of point)/Distance^2))
  • Attractive Force Potentials for Sun = Universal Constant*Mass of the Sun*(Mean Radius of the Earth^2/Distance^3)*Harmonic Polynomial Expansion Terms for Sun
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