BOD5 given Oxygen Required in Aeration Tank Solution

STEP 0: Pre-Calculation Summary
Formula Used
5 days BOD = Ultimate BOD*(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge))
BOD5 = BODu*(Qs*(Qi-Qo))/(O2+(1.42*Qw*XR))
This formula uses 8 Variables
Variables Used
5 days BOD - (Measured in Kilogram per Cubic Meter) - 5 days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C.
Ultimate BOD - (Measured in Kilogram per Cubic Meter) - Ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time.
Sewage Discharge - (Measured in Cubic Meter per Second) - Sewage discharge is the flow rate of sewage when it is being discharged in the river.
Influent BOD - (Measured in Kilogram per Cubic Meter) - Influent BOD is the total amount of BOD which is present in the incoming sewage.
Effluent BOD - (Measured in Kilogram per Cubic Meter) - Effluent BOD is the amount of BOD present in the outing sewage.
Theoretical Oxygen Requirement - (Measured in Kilogram per Second) - Theoretical oxygen requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products.
Volume of Wasted Sludge per day - (Measured in Cubic Meter per Second) - Volume of wasted sludge per day is measured in terms of discharge.
MLSS in returned or wasted sludge - (Measured in Kilogram per Cubic Meter) - MLSS in returned or wasted sludge is the mixed liquor suspended solids in returned sludge in terms of mg per litre.
STEP 1: Convert Input(s) to Base Unit
Ultimate BOD: 2 Milligram per Liter --> 0.002 Kilogram per Cubic Meter (Check conversion here)
Sewage Discharge: 10 Cubic Meter per Second --> 10 Cubic Meter per Second No Conversion Required
Influent BOD: 11.2 Milligram per Liter --> 0.0112 Kilogram per Cubic Meter (Check conversion here)
Effluent BOD: 0.4 Milligram per Liter --> 0.0004 Kilogram per Cubic Meter (Check conversion here)
Theoretical Oxygen Requirement: 2.5 Milligram per Day --> 2.89351851851852E-11 Kilogram per Second (Check conversion here)
Volume of Wasted Sludge per day: 9.5 Cubic Meter per Second --> 9.5 Cubic Meter per Second No Conversion Required
MLSS in returned or wasted sludge: 2 Milligram per Liter --> 0.002 Kilogram per Cubic Meter (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
BOD5 = BODu*(Qs*(Qi-Qo))/(O2+(1.42*Qw*XR)) --> 0.002*(10*(0.0112-0.0004))/(2.89351851851852E-11+(1.42*9.5*0.002))
Evaluating ... ...
BOD5 = 0.00800593031016853
STEP 3: Convert Result to Output's Unit
0.00800593031016853 Kilogram per Cubic Meter -->8.00593031016853 Milligram per Liter (Check conversion here)
FINAL ANSWER
8.00593031016853 8.00593 Milligram per Liter <-- 5 days BOD
(Calculation completed in 00.020 seconds)

Credits

Created by Suraj Kumar
Birsa Institute of Technology (BIT), Sindri
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3 BOD5 Calculators

BOD5 given Oxygen Required in Aeration Tank
Go 5 days BOD = Ultimate BOD*(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge))
BOD5 given Ratio of BOD to Ultimate BOD
Go 5 days BOD = Ratio of BOD to Ultimate BOD*Ultimate BOD
BOD5 when Ratio of BOD to Ultimate BOD is 0.68
Go 5 days BOD = Ultimate BOD*0.68

BOD5 given Oxygen Required in Aeration Tank Formula

5 days BOD = Ultimate BOD*(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge))
BOD5 = BODu*(Qs*(Qi-Qo))/(O2+(1.42*Qw*XR))

What is BOD ?

Biochemical oxygen demand is the amount of dissolved oxygen needed by aerobic biological organisms to break down organic material present in a given water sample at certain temperature over a specific time period.

How to Calculate BOD5 given Oxygen Required in Aeration Tank?

BOD5 given Oxygen Required in Aeration Tank calculator uses 5 days BOD = Ultimate BOD*(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)) to calculate the 5 days BOD, BOD5 given Oxygen Required in Aeration Tank calculates value of 5 days bod when we have prior information of other parameters used. 5 days BOD is denoted by BOD5 symbol.

How to calculate BOD5 given Oxygen Required in Aeration Tank using this online calculator? To use this online calculator for BOD5 given Oxygen Required in Aeration Tank, enter Ultimate BOD (BODu), Sewage Discharge (Qs), Influent BOD (Qi), Effluent BOD (Qo), Theoretical Oxygen Requirement (O2), Volume of Wasted Sludge per day (Qw) & MLSS in returned or wasted sludge (XR) and hit the calculate button. Here is how the BOD5 given Oxygen Required in Aeration Tank calculation can be explained with given input values -> 8005.93 = 0.002*(10*(0.0112-0.0004))/(2.89351851851852E-11+(1.42*9.5*0.002)).

FAQ

What is BOD5 given Oxygen Required in Aeration Tank?
BOD5 given Oxygen Required in Aeration Tank calculates value of 5 days bod when we have prior information of other parameters used and is represented as BOD5 = BODu*(Qs*(Qi-Qo))/(O2+(1.42*Qw*XR)) or 5 days BOD = Ultimate BOD*(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)). Ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time, Sewage discharge is the flow rate of sewage when it is being discharged in the river, Influent BOD is the total amount of BOD which is present in the incoming sewage, Effluent BOD is the amount of BOD present in the outing sewage, Theoretical oxygen requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products, Volume of wasted sludge per day is measured in terms of discharge & MLSS in returned or wasted sludge is the mixed liquor suspended solids in returned sludge in terms of mg per litre.
How to calculate BOD5 given Oxygen Required in Aeration Tank?
BOD5 given Oxygen Required in Aeration Tank calculates value of 5 days bod when we have prior information of other parameters used is calculated using 5 days BOD = Ultimate BOD*(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in returned or wasted sludge)). To calculate BOD5 given Oxygen Required in Aeration Tank, you need Ultimate BOD (BODu), Sewage Discharge (Qs), Influent BOD (Qi), Effluent BOD (Qo), Theoretical Oxygen Requirement (O2), Volume of Wasted Sludge per day (Qw) & MLSS in returned or wasted sludge (XR). With our tool, you need to enter the respective value for Ultimate BOD, Sewage Discharge, Influent BOD, Effluent BOD, Theoretical Oxygen Requirement, Volume of Wasted Sludge per day & MLSS in returned or wasted sludge and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate 5 days BOD?
In this formula, 5 days BOD uses Ultimate BOD, Sewage Discharge, Influent BOD, Effluent BOD, Theoretical Oxygen Requirement, Volume of Wasted Sludge per day & MLSS in returned or wasted sludge. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • 5 days BOD = Ratio of BOD to Ultimate BOD*Ultimate BOD
  • 5 days BOD = Ultimate BOD*0.68
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