Depression Head in Well given Pumping Stopped and Constant with Base 10 Solution

STEP 0: Pre-Calculation Summary
Formula Used
Depression Head 1 = Depression Head 2*10^((Constant*Time)/(Cross Sectional Area*2.303))
h1 = h2*10^((K*t)/(Acs*2.303))
This formula uses 5 Variables
Variables Used
Depression Head 1 - (Measured in Meter) - Depression Head 1 is the difference of level of waters table and the water level in the well when pumping stopped.
Depression Head 2 - (Measured in Meter) - Depression Head 2 is the difference of level of waters table and the water level in the well when pumping stopped.
Constant - Constant depending on the soil at the base of the well.
Time - (Measured in Hour) - Time can be defined as the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Cross Sectional Area - (Measured in Square Meter) - Cross Sectional Area is the area of a two-dimensional shape that is obtained when a three-dimensional shape is sliced perpendicular to some specified axis at a point.
STEP 1: Convert Input(s) to Base Unit
Depression Head 2: 10 Meter --> 10 Meter No Conversion Required
Constant: 5 --> No Conversion Required
Time: 4 Hour --> 4 Hour No Conversion Required
Cross Sectional Area: 20 Square Meter --> 20 Square Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
h1 = h2*10^((K*t)/(Acs*2.303)) --> 10*10^((5*4)/(20*2.303))
Evaluating ... ...
h1 = 27.177921486562
STEP 3: Convert Result to Output's Unit
27.177921486562 Meter --> No Conversion Required
FINAL ANSWER
27.177921486562 27.17792 Meter <-- Depression Head 1
(Calculation completed in 00.004 seconds)

Credits

Created by Suraj Kumar
Birsa Institute of Technology (BIT), Sindri
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11 Depression Head when Pumping Stopped Calculators

Depression Head in Well given Pumping Stopped with Discharge
Go Depression Head 1 = Depression Head 2*10^((Discharge*Total time interval)/(Cross Sectional Area*Constant Depression Head*2.303))
Depression Head in Well given Pumping Stopped and Constant
Go Depression Head 1 = Depression Head 2*exp((Constant*Time)/Cross Sectional Area)
Depression Head in Well given Pumping Stopped and Constant with Base 10
Go Depression Head 1 = Depression Head 2*10^((Constant*Time)/(Cross Sectional Area*2.303))
Depression Head in Well when Pumping Stopped
Go Depression Head 1 = Depression Head 2*exp(Specific Capacity*Time)
Depression Head in Well when Pumping Stopped with Base 10
Go Depression Head 1 = Depression Head 2*10^((Specific Capacity*Time)/2.303)
Depression Head in well given pumping stopped and clay soil is present
Go Depression Head 1 = Depression Head 2*exp(0.25*Total time interval)
Depression Head in Well given Pumping Stopped and Fine Sand is Present
Go Depression Head 1 = Depression Head 2*exp(0.5*Total time interval)
Depression Head in Well given Pumping Stopped and Coarse Sand is Present
Go Depression Head 1 = Depression Head 2*exp(1*Total time interval)
Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present
Go Depression Head 1 = Depression Head 2*10^((0.25*Total time interval)/2.303)
Depression Head in Well given Pumping Stopped with Base 10 and Fine Sand is Present
Go Depression Head 1 = Depression Head 2*10^((0.5*Total time interval)/2.303)
Depression Head in Well given Pumping Stopped with Base 10 and Coarse Sand is Present
Go Depression Head 1 = Depression Head 2*10^((1*Total time interval)/2.303)

Depression Head in Well given Pumping Stopped and Constant with Base 10 Formula

Depression Head 1 = Depression Head 2*10^((Constant*Time)/(Cross Sectional Area*2.303))
h1 = h2*10^((K*t)/(Acs*2.303))

What is specific capacity ?

Specific capacity is a quantity that which a water well can produce per unit of drawdown. It is normally obtained from a step drawdown test.

How to Calculate Depression Head in Well given Pumping Stopped and Constant with Base 10?

Depression Head in Well given Pumping Stopped and Constant with Base 10 calculator uses Depression Head 1 = Depression Head 2*10^((Constant*Time)/(Cross Sectional Area*2.303)) to calculate the Depression Head 1, Depression Head in Well given Pumping Stopped and Constant with Base 10 calculates value of depression head in well when we have prior information of other parameters used. Depression Head 1 is denoted by h1 symbol.

How to calculate Depression Head in Well given Pumping Stopped and Constant with Base 10 using this online calculator? To use this online calculator for Depression Head in Well given Pumping Stopped and Constant with Base 10, enter Depression Head 2 (h2), Constant (K), Time (t) & Cross Sectional Area (Acs) and hit the calculate button. Here is how the Depression Head in Well given Pumping Stopped and Constant with Base 10 calculation can be explained with given input values -> 27.17792 = 10*10^((5*14400)/(20*2.303)).

FAQ

What is Depression Head in Well given Pumping Stopped and Constant with Base 10?
Depression Head in Well given Pumping Stopped and Constant with Base 10 calculates value of depression head in well when we have prior information of other parameters used and is represented as h1 = h2*10^((K*t)/(Acs*2.303)) or Depression Head 1 = Depression Head 2*10^((Constant*Time)/(Cross Sectional Area*2.303)). Depression Head 2 is the difference of level of waters table and the water level in the well when pumping stopped, Constant depending on the soil at the base of the well, Time can be defined as the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future & Cross Sectional Area is the area of a two-dimensional shape that is obtained when a three-dimensional shape is sliced perpendicular to some specified axis at a point.
How to calculate Depression Head in Well given Pumping Stopped and Constant with Base 10?
Depression Head in Well given Pumping Stopped and Constant with Base 10 calculates value of depression head in well when we have prior information of other parameters used is calculated using Depression Head 1 = Depression Head 2*10^((Constant*Time)/(Cross Sectional Area*2.303)). To calculate Depression Head in Well given Pumping Stopped and Constant with Base 10, you need Depression Head 2 (h2), Constant (K), Time (t) & Cross Sectional Area (Acs). With our tool, you need to enter the respective value for Depression Head 2, Constant, Time & Cross Sectional Area and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Depression Head 1?
In this formula, Depression Head 1 uses Depression Head 2, Constant, Time & Cross Sectional Area. We can use 10 other way(s) to calculate the same, which is/are as follows -
  • Depression Head 1 = Depression Head 2*exp(Specific Capacity*Time)
  • Depression Head 1 = Depression Head 2*10^((Specific Capacity*Time)/2.303)
  • Depression Head 1 = Depression Head 2*exp(0.25*Total time interval)
  • Depression Head 1 = Depression Head 2*10^((0.25*Total time interval)/2.303)
  • Depression Head 1 = Depression Head 2*exp(0.5*Total time interval)
  • Depression Head 1 = Depression Head 2*10^((0.5*Total time interval)/2.303)
  • Depression Head 1 = Depression Head 2*exp(1*Total time interval)
  • Depression Head 1 = Depression Head 2*10^((1*Total time interval)/2.303)
  • Depression Head 1 = Depression Head 2*exp((Constant*Time)/Cross Sectional Area)
  • Depression Head 1 = Depression Head 2*10^((Discharge*Total time interval)/(Cross Sectional Area*Constant Depression Head*2.303))
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