Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions Solution

STEP 0: Pre-Calculation Summary
Formula Used
Excess Gibbs Free Energy = ([R]*Temperature of Liquid Vapour System)*(Mole Fraction of Component 1 in Liquid Phase*ln(Activity Coefficient of Component 1)+Mole Fraction of Component 2 in Liquid Phase*ln(Activity Coefficient of Component 2))
GE = ([R]*TVLE)*(x1*ln(γ1)+x2*ln(γ2))
This formula uses 1 Constants, 1 Functions, 6 Variables
Constants Used
[R] - Universal gas constant Value Taken As 8.31446261815324
Functions Used
ln - The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function., ln(Number)
Variables Used
Excess Gibbs Free Energy - (Measured in Joule) - Excess Gibbs Free Energy is the Gibbs energy of a solution in excess of what it would be if it were ideal.
Temperature of Liquid Vapour System - (Measured in Kelvin) - Temperature of liquid vapour system is the degree or intensity of heat present in a substance or object.
Mole Fraction of Component 1 in Liquid Phase - The mole fraction of component 1 in liquid phase can be defined as the ratio of the number of moles a component 1 to the total number of moles of components present in the liquid phase.
Activity Coefficient of Component 1 - Activity Coefficient of Component 1 is a factor used in thermodynamics to account for deviations from ideal behaviour in a mixture of chemical substances.
Mole Fraction of Component 2 in Liquid Phase - The mole fraction of component 2 in liquid phase can be defined as the ratio of the number of moles a component 2 to the total number of moles of components present in the liquid phase.
Activity Coefficient of Component 2 - Activity coefficient of component 2 is a factor used in thermodynamics to account for deviations from ideal behaviour in a mixture of chemical substances.
STEP 1: Convert Input(s) to Base Unit
Temperature of Liquid Vapour System: 400 Kelvin --> 400 Kelvin No Conversion Required
Mole Fraction of Component 1 in Liquid Phase: 0.4 --> No Conversion Required
Activity Coefficient of Component 1: 1.13 --> No Conversion Required
Mole Fraction of Component 2 in Liquid Phase: 0.6 --> No Conversion Required
Activity Coefficient of Component 2: 1.12 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
GE = ([R]*TVLE)*(x1*ln(γ1)+x2*ln(γ2)) --> ([R]*400)*(0.4*ln(1.13)+0.6*ln(1.12))
Evaluating ... ...
GE = 388.73193838228
STEP 3: Convert Result to Output's Unit
388.73193838228 Joule --> No Conversion Required
FINAL ANSWER
388.73193838228 388.7319 Joule <-- Excess Gibbs Free Energy
(Calculation completed in 00.004 seconds)

Credits

Created by Shivam Sinha
National Institute Of Technology (NIT), Surathkal
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Verified by Pragati Jaju
College Of Engineering (COEP), Pune
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9 Fitting Activity Coefficient Models to VLE Data Calculators

Vapour Fugacity Coefficient of Comp. 1 using Sat. Pressure and Second Virial Coefficients
Go Fugacity Coefficient of Component 1 = exp((Second Virial Coefficient 11*(Pressure in Liquid Vapour System-Saturated Pressure of Component 1)+Pressure in Liquid Vapour System*(Mole Fraction of Component 2 in Vapour Phase^2)*(2*Second Virial Coefficient 12-Second Virial Coefficient 11-Second Virial Coefficient 22))/([R]*Temperature of Liquid Vapour System))
Vapour Fugacity Coefficient of Comp. 2 using Sat. Pressure and Second Virial Coefficients
Go Fugacity Coefficient of Component 2 = exp((Second Virial Coefficient 22*(Pressure in Liquid Vapour System-Saturated Pressure of Component 2)+Pressure in Liquid Vapour System*(Mole Fraction of Component 1 in Vapour Phase^2)*(2*Second Virial Coefficient 12-Second Virial Coefficient 11-Second Virial Coefficient 22))/([R]*Temperature of Liquid Vapour System))
Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions
Go Excess Gibbs Free Energy = ([R]*Temperature of Liquid Vapour System)*(Mole Fraction of Component 1 in Liquid Phase*ln(Activity Coefficient of Component 1)+Mole Fraction of Component 2 in Liquid Phase*ln(Activity Coefficient of Component 2))
Saturated Vapour Fugacity Coefficient of Comp. 1 using Sat. Pressure and Second Virial Coefficient
Go Saturated Fugacity Coefficient of Component 1 = exp((Second Virial Coefficient 11*Saturated Pressure of Component 1)/([R]*Temperature of Liquid Vapour System))
Saturated Vapour Fugacity Coefficient of Comp. 2 using Sat. Pressure and Second Virial Coefficient
Go Saturated Fugacity Coefficient of Component 2 = exp((Second Virial Coefficient 22*Saturated Pressure of Component 2)/([R]*Temperature of Liquid Vapour System))
Second Virial Coefficient of Comp. 1 using Sat. Pressure and Saturated Vapour Fugacity Coefficient
Go Second Virial Coefficient 11 = (ln(Saturated Fugacity Coefficient of Component 1)*[R]*Temperature of Liquid Vapour System)/Saturated Pressure of Component 1
Second Virial Coefficient of Comp. 2 using Saturated Pressure and Sat. Vapour Fugacity Coefficient
Go Second Virial Coefficient 22 = (ln(Saturated Fugacity Coefficient of Component 2)*[R]*Temperature of Liquid Vapour System)/Saturated Pressure of Component 2
Saturated Pressure of Comp. 1 using Second Virial Coefficient and Sat. Vapour Fugacity Coefficient
Go Saturated Pressure of Component 1 = (ln(Saturated Fugacity Coefficient of Component 1)*[R]*Temperature of Liquid Vapour System)/Second Virial Coefficient 11
Saturated Pressure of Comp. 2 using Second Virial Coefficient and Sat. Vapour Fugacity Coefficient
Go Saturated Pressure of Component 2 = (ln(Saturated Fugacity Coefficient of Component 2)*[R]*Temperature of Liquid Vapour System)/Second Virial Coefficient 22

Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions Formula

Excess Gibbs Free Energy = ([R]*Temperature of Liquid Vapour System)*(Mole Fraction of Component 1 in Liquid Phase*ln(Activity Coefficient of Component 1)+Mole Fraction of Component 2 in Liquid Phase*ln(Activity Coefficient of Component 2))
GE = ([R]*TVLE)*(x1*ln(γ1)+x2*ln(γ2))

What is Gibbs Free Energy?

The Gibbs free energy (or Gibbs energy) is a thermodynamic potential that can be used to calculate the maximum reversible work that may be performed by a thermodynamic system at a constant temperature and pressure. The Gibbs free energy measured in joules in SI) is the maximum amount of non-expansion work that can be extracted from a thermodynamically closed system (can exchange heat and work with its surroundings, but not matter). This maximum can be attained only in a completely reversible process. When a system transforms reversibly from an initial state to a final state, the decrease in Gibbs free energy equals the work done by the system to its surroundings, minus the work of the pressure forces.

What is Duhem’s Theorem?

For any closed system formed from known amounts of prescribed chemical species, the equilibrium state is completely determined when any two independent variables are fixed. The two independent variables subject to specification may in general be either intensive or extensive. However, the number of independent intensive variables is given by the phase rule. Thus when F = 1, at least one of the two variables must be extensive, and when F = 0, both must be extensive.

How to Calculate Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions?

Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions calculator uses Excess Gibbs Free Energy = ([R]*Temperature of Liquid Vapour System)*(Mole Fraction of Component 1 in Liquid Phase*ln(Activity Coefficient of Component 1)+Mole Fraction of Component 2 in Liquid Phase*ln(Activity Coefficient of Component 2)) to calculate the Excess Gibbs Free Energy, The Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions formula is defined as the product of the universal gas constant, temperature and the summation of the product of the mole fraction of i th component and the natural logarithm of the activity coefficient of component i, where for binary system i = 2. Excess Gibbs Free Energy is denoted by GE symbol.

How to calculate Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions using this online calculator? To use this online calculator for Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions, enter Temperature of Liquid Vapour System (TVLE), Mole Fraction of Component 1 in Liquid Phase (x1), Activity Coefficient of Component 1 1), Mole Fraction of Component 2 in Liquid Phase (x2) & Activity Coefficient of Component 2 2) and hit the calculate button. Here is how the Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions calculation can be explained with given input values -> 388.7319 = ([R]*400)*(0.4*ln(1.13)+0.6*ln(1.12)).

FAQ

What is Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions?
The Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions formula is defined as the product of the universal gas constant, temperature and the summation of the product of the mole fraction of i th component and the natural logarithm of the activity coefficient of component i, where for binary system i = 2 and is represented as GE = ([R]*TVLE)*(x1*ln(γ1)+x2*ln(γ2)) or Excess Gibbs Free Energy = ([R]*Temperature of Liquid Vapour System)*(Mole Fraction of Component 1 in Liquid Phase*ln(Activity Coefficient of Component 1)+Mole Fraction of Component 2 in Liquid Phase*ln(Activity Coefficient of Component 2)). Temperature of liquid vapour system is the degree or intensity of heat present in a substance or object, The mole fraction of component 1 in liquid phase can be defined as the ratio of the number of moles a component 1 to the total number of moles of components present in the liquid phase, Activity Coefficient of Component 1 is a factor used in thermodynamics to account for deviations from ideal behaviour in a mixture of chemical substances, The mole fraction of component 2 in liquid phase can be defined as the ratio of the number of moles a component 2 to the total number of moles of components present in the liquid phase & Activity coefficient of component 2 is a factor used in thermodynamics to account for deviations from ideal behaviour in a mixture of chemical substances.
How to calculate Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions?
The Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions formula is defined as the product of the universal gas constant, temperature and the summation of the product of the mole fraction of i th component and the natural logarithm of the activity coefficient of component i, where for binary system i = 2 is calculated using Excess Gibbs Free Energy = ([R]*Temperature of Liquid Vapour System)*(Mole Fraction of Component 1 in Liquid Phase*ln(Activity Coefficient of Component 1)+Mole Fraction of Component 2 in Liquid Phase*ln(Activity Coefficient of Component 2)). To calculate Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions, you need Temperature of Liquid Vapour System (TVLE), Mole Fraction of Component 1 in Liquid Phase (x1), Activity Coefficient of Component 1 1), Mole Fraction of Component 2 in Liquid Phase (x2) & Activity Coefficient of Component 2 2). With our tool, you need to enter the respective value for Temperature of Liquid Vapour System, Mole Fraction of Component 1 in Liquid Phase, Activity Coefficient of Component 1, Mole Fraction of Component 2 in Liquid Phase & Activity Coefficient of Component 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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