Heat Dissipation from Infinitely Long Fin Solution

STEP 0: Pre-Calculation Summary
Formula Used
Fin Heat Transfer Rate = ((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)^0.5)*(Surface Temperature-Surrounding Temperature)
Qfin = ((Pfin*htransfer*kfin*Ac)^0.5)*(Tw-Ts)
This formula uses 7 Variables
Variables Used
Fin Heat Transfer Rate - (Measured in Watt) - Fin Heat Transfer Rate is that extend from an object to increase the rate of heat transfer to or from the environment by increasing convection.
Perimeter of Fin - (Measured in Meter) - The perimeter of fin is the total distance around the edge of the figure.
Heat Transfer Coefficient - (Measured in Watt per Square Meter per Kelvin) - The Heat Transfer Coefficient is the heat transferred per unit area per kelvin. Thus area is included in the equation as it represents the area over which the transfer of heat takes place.
Thermal Conductivity of Fin - (Measured in Watt per Meter per K) - Thermal Conductivity of Fin is rate of heat passes through Fin, expressed as amount of heat flows per unit time through a unit area with a temperature gradient of one degree per unit distance.
Cross Sectional Area - (Measured in Square Meter) - Cross sectional area is the area of a two-dimensional shape that is obtained when a three dimensional shape is sliced perpendicular to some specified axis at a point.
Surface Temperature - (Measured in Kelvin) - Surface Temperature is the temperature at or near a surface. Specifically, it may refer to as Surface air temperature, the temperature of the air near the surface of the earth.
Surrounding Temperature - (Measured in Kelvin) - The Surrounding Temperature of a body is temperature of the surroundings body.
STEP 1: Convert Input(s) to Base Unit
Perimeter of Fin: 25 Meter --> 25 Meter No Conversion Required
Heat Transfer Coefficient: 13.2 Watt per Square Meter per Kelvin --> 13.2 Watt per Square Meter per Kelvin No Conversion Required
Thermal Conductivity of Fin: 10.18 Watt per Meter per K --> 10.18 Watt per Meter per K No Conversion Required
Cross Sectional Area: 10.2 Square Meter --> 10.2 Square Meter No Conversion Required
Surface Temperature: 305 Kelvin --> 305 Kelvin No Conversion Required
Surrounding Temperature: 100 Kelvin --> 100 Kelvin No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Qfin = ((Pfin*htransfer*kfin*Ac)^0.5)*(Tw-Ts) --> ((25*13.2*10.18*10.2)^0.5)*(305-100)
Evaluating ... ...
Qfin = 37947.6429702821
STEP 3: Convert Result to Output's Unit
37947.6429702821 Watt --> No Conversion Required
FINAL ANSWER
37947.6429702821 37947.64 Watt <-- Fin Heat Transfer Rate
(Calculation completed in 00.004 seconds)

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9 Heat Transfer from Extended Surfaces (Fins) Calculators

Heat Dissipation from Fin Losing Heat at End Tip
Go Fin Heat Transfer Rate = (sqrt(Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area))*(Surface Temperature-Surrounding Temperature)*((tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin)+(Heat Transfer Coefficient)/(Thermal Conductivity of Fin*(sqrt(Perimeter of Fin*Heat Transfer Coefficient/Thermal Conductivity of Fin*Cross Sectional Area)))))/(1+tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin*(Heat Transfer Coefficient)/(Thermal Conductivity of Fin*(sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area))))))
Heat Dissipation from Fin Insulated at End Tip
Go Fin Heat Transfer Rate = (sqrt((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)))*(Surface Temperature-Surrounding Temperature)*tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin)
Heat Dissipation from Infinitely Long Fin
Go Fin Heat Transfer Rate = ((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)^0.5)*(Surface Temperature-Surrounding Temperature)
Heat Transfer in Fins given Fin Efficiency
Go Fin Heat Transfer Rate = Overall Heat Transfer Coefficient*Area*Fin Efficiency*Overall Difference in Temperature
Newton's Law of Cooling
Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Temperature of Characteristic Fluid)
Biot Number using Characteristic Length
Go Biot Number = (Heat Transfer Coefficient*Characteristic Length)/(Thermal Conductivity of Fin)
Correction Length for Cylindrical Fin with Non-Adiabatic Tip
Go Correction Length for Cylindrical Fin = Length of Fin+(Diameter of Cylindrical Fin/4)
Correction Length for Thin Rectangular Fin with Non-Adiabatic Tip
Go Correction Length for Thin Rectangular Fin = Length of Fin+(Thickness of Fin/2)
Correction Length for Square Fin with Non-Adiabatic Tip
Go Correction Length for Sqaure Fin = Length of Fin+(Width of Fin/4)

20 Heat Transfer from Extended Surfaces (Fins), Critical Thickness of Insulation and Thermal Resistance Calculators

Heat Dissipation from Fin Losing Heat at End Tip
Go Fin Heat Transfer Rate = (sqrt(Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area))*(Surface Temperature-Surrounding Temperature)*((tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin)+(Heat Transfer Coefficient)/(Thermal Conductivity of Fin*(sqrt(Perimeter of Fin*Heat Transfer Coefficient/Thermal Conductivity of Fin*Cross Sectional Area)))))/(1+tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin*(Heat Transfer Coefficient)/(Thermal Conductivity of Fin*(sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area))))))
Heat Dissipation from Fin Insulated at End Tip
Go Fin Heat Transfer Rate = (sqrt((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)))*(Surface Temperature-Surrounding Temperature)*tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin)
Heat Dissipation from Infinitely Long Fin
Go Fin Heat Transfer Rate = ((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)^0.5)*(Surface Temperature-Surrounding Temperature)
Thermal Resistance for Conduction at Tube Wall
Go Thermal Resistance = (ln(Outer Radius of Cylinder/Inner Radius of Cylinder))/(2*pi*Thermal Conductivity*Length of Cylinder)
Heat Transfer in Fins given Fin Efficiency
Go Fin Heat Transfer Rate = Overall Heat Transfer Coefficient*Area*Fin Efficiency*Overall Difference in Temperature
Newton's Law of Cooling
Go Heat Flux = Heat Transfer Coefficient*(Surface Temperature-Temperature of Characteristic Fluid)
Biot Number using Characteristic Length
Go Biot Number = (Heat Transfer Coefficient*Characteristic Length)/(Thermal Conductivity of Fin)
Critical Radius of Insulation of Hollow Sphere
Go Critical Radius of Insulation = 2*Thermal Conductivity of Insulation/External Convection Heat Transfer Coefficient
Critical Radius of Insulation of Cylinder
Go Critical Radius of Insulation = Thermal Conductivity of Insulation/External Convection Heat Transfer Coefficient
Correction Length for Cylindrical Fin with Non-Adiabatic Tip
Go Correction Length for Cylindrical Fin = Length of Fin+(Diameter of Cylindrical Fin/4)
Outside Heat Transfer Coefficient given Thermal Resistance
Go External Convection Heat Transfer Coefficient = 1/(Thermal Resistance*Outside Area)
Thermal Resistance for Convection at Outer Surface
Go Thermal Resistance = 1/(External Convection Heat Transfer Coefficient*Outside Area)
Outside Area given Outer Thermal Resistance
Go Outside Area = 1/(External Convection Heat Transfer Coefficient*Thermal Resistance)
Inner Heat Transfer Coefficient given Inner Thermal Resistance
Go Inside Convection Heat Transfer Coefficient = 1/(Inside Area*Thermal Resistance)
Inside Area given Thermal Resistance for Inner Surface
Go Inside Area = 1/(Inside Convection Heat Transfer Coefficient*Thermal Resistance)
Thermal Resistance for Convection at Inner Surface
Go Thermal Resistance = 1/(Inside Area*Inside Convection Heat Transfer Coefficient)
Correction Length for Thin Rectangular Fin with Non-Adiabatic Tip
Go Correction Length for Thin Rectangular Fin = Length of Fin+(Thickness of Fin/2)
Volumetric Heat Generation in Current Carrying Electrical Conductor
Go Volumetric Heat Generation = (Electric Current Density^2)*Resistivity
Total Thermal Resistance
Go Total Thermal Resistance = 1/(Overall Heat Transfer Coefficient*Area)
Correction Length for Square Fin with Non-Adiabatic Tip
Go Correction Length for Sqaure Fin = Length of Fin+(Width of Fin/4)

Heat Dissipation from Infinitely Long Fin Formula

Fin Heat Transfer Rate = ((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)^0.5)*(Surface Temperature-Surrounding Temperature)
Qfin = ((Pfin*htransfer*kfin*Ac)^0.5)*(Tw-Ts)

What is Heat Dissipation?

Heat dissipation occurs when an object that is hotter than other objects is placed in an environment where the heat of the hotter object is transferred to the colder objects and the surrounding environment.

How to Calculate Heat Dissipation from Infinitely Long Fin?

Heat Dissipation from Infinitely Long Fin calculator uses Fin Heat Transfer Rate = ((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)^0.5)*(Surface Temperature-Surrounding Temperature) to calculate the Fin Heat Transfer Rate, The Heat Dissipation from Infinitely Long Fin formula is defined as surfaces that extend from an object to increase the rate of heat transfer to or from the environment by increasing convection. Fin Heat Transfer Rate is denoted by Qfin symbol.

How to calculate Heat Dissipation from Infinitely Long Fin using this online calculator? To use this online calculator for Heat Dissipation from Infinitely Long Fin, enter Perimeter of Fin (Pfin), Heat Transfer Coefficient (htransfer), Thermal Conductivity of Fin (kfin), Cross Sectional Area (Ac), Surface Temperature (Tw) & Surrounding Temperature (Ts) and hit the calculate button. Here is how the Heat Dissipation from Infinitely Long Fin calculation can be explained with given input values -> 37947.64 = ((25*13.2*10.18*10.2)^0.5)*(305-100).

FAQ

What is Heat Dissipation from Infinitely Long Fin?
The Heat Dissipation from Infinitely Long Fin formula is defined as surfaces that extend from an object to increase the rate of heat transfer to or from the environment by increasing convection and is represented as Qfin = ((Pfin*htransfer*kfin*Ac)^0.5)*(Tw-Ts) or Fin Heat Transfer Rate = ((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)^0.5)*(Surface Temperature-Surrounding Temperature). The perimeter of fin is the total distance around the edge of the figure, The Heat Transfer Coefficient is the heat transferred per unit area per kelvin. Thus area is included in the equation as it represents the area over which the transfer of heat takes place, Thermal Conductivity of Fin is rate of heat passes through Fin, expressed as amount of heat flows per unit time through a unit area with a temperature gradient of one degree per unit distance, Cross sectional area is the area of a two-dimensional shape that is obtained when a three dimensional shape is sliced perpendicular to some specified axis at a point, Surface Temperature is the temperature at or near a surface. Specifically, it may refer to as Surface air temperature, the temperature of the air near the surface of the earth & The Surrounding Temperature of a body is temperature of the surroundings body.
How to calculate Heat Dissipation from Infinitely Long Fin?
The Heat Dissipation from Infinitely Long Fin formula is defined as surfaces that extend from an object to increase the rate of heat transfer to or from the environment by increasing convection is calculated using Fin Heat Transfer Rate = ((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)^0.5)*(Surface Temperature-Surrounding Temperature). To calculate Heat Dissipation from Infinitely Long Fin, you need Perimeter of Fin (Pfin), Heat Transfer Coefficient (htransfer), Thermal Conductivity of Fin (kfin), Cross Sectional Area (Ac), Surface Temperature (Tw) & Surrounding Temperature (Ts). With our tool, you need to enter the respective value for Perimeter of Fin, Heat Transfer Coefficient, Thermal Conductivity of Fin, Cross Sectional Area, Surface Temperature & Surrounding Temperature and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Fin Heat Transfer Rate?
In this formula, Fin Heat Transfer Rate uses Perimeter of Fin, Heat Transfer Coefficient, Thermal Conductivity of Fin, Cross Sectional Area, Surface Temperature & Surrounding Temperature. We can use 6 other way(s) to calculate the same, which is/are as follows -
  • Fin Heat Transfer Rate = (sqrt((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)))*(Surface Temperature-Surrounding Temperature)*tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin)
  • Fin Heat Transfer Rate = (sqrt(Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area))*(Surface Temperature-Surrounding Temperature)*((tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin)+(Heat Transfer Coefficient)/(Thermal Conductivity of Fin*(sqrt(Perimeter of Fin*Heat Transfer Coefficient/Thermal Conductivity of Fin*Cross Sectional Area)))))/(1+tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin*(Heat Transfer Coefficient)/(Thermal Conductivity of Fin*(sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area))))))
  • Fin Heat Transfer Rate = Overall Heat Transfer Coefficient*Area*Fin Efficiency*Overall Difference in Temperature
  • Fin Heat Transfer Rate = (sqrt((Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area)))*(Surface Temperature-Surrounding Temperature)*tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin)
  • Fin Heat Transfer Rate = (sqrt(Perimeter of Fin*Heat Transfer Coefficient*Thermal Conductivity of Fin*Cross Sectional Area))*(Surface Temperature-Surrounding Temperature)*((tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin)+(Heat Transfer Coefficient)/(Thermal Conductivity of Fin*(sqrt(Perimeter of Fin*Heat Transfer Coefficient/Thermal Conductivity of Fin*Cross Sectional Area)))))/(1+tanh((sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area)))*Length of Fin*(Heat Transfer Coefficient)/(Thermal Conductivity of Fin*(sqrt((Perimeter of Fin*Heat Transfer Coefficient)/(Thermal Conductivity of Fin*Cross Sectional Area))))))
  • Fin Heat Transfer Rate = Overall Heat Transfer Coefficient*Area*Fin Efficiency*Overall Difference in Temperature
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