Heat rejected during cooling process Solution

STEP 0: Pre-Calculation Summary
Formula Used
Heat Rejected = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Temperature at the end of cooling process)
QR = ma*Cp*(Tt'-T4)
This formula uses 5 Variables
Variables Used
Heat Rejected - (Measured in Joule per Kilogram) - Heat Rejected is the heat released during any of the thermodynamic processes.
Mass of Air - (Measured in Kilogram per Second) - Mass of air is both a property of air and a measure of its resistance to acceleration when a net force is applied.
Specific Heat Capacity at Constant Pressure - (Measured in Joule per Kilogram per K) - Specific Heat Capacity at Constant Pressure means the amount of heat that is required to raise the temperature of a unit mass of gas by 1 degree at constant pressure.
Actual End Temp of Isentropic Compression - (Measured in Kelvin) - Actual End Temp of Isentropic Compression is greater than the ideal temperature.
Temperature at the end of cooling process - (Measured in Kelvin) - Temperature at the end of cooling process is also the temperature at which isentropic expansion starts.
STEP 1: Convert Input(s) to Base Unit
Mass of Air: 120 Kilogram per Minute --> 2 Kilogram per Second (Check conversion here)
Specific Heat Capacity at Constant Pressure: 1.005 Kilojoule per Kilogram per K --> 1005 Joule per Kilogram per K (Check conversion here)
Actual End Temp of Isentropic Compression: 350 Kelvin --> 350 Kelvin No Conversion Required
Temperature at the end of cooling process: 385 Kelvin --> 385 Kelvin No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
QR = ma*Cp*(Tt'-T4) --> 2*1005*(350-385)
Evaluating ... ...
QR = -70350
STEP 3: Convert Result to Output's Unit
-70350 Joule per Kilogram -->-70.35 Kilojoule per Kilogram (Check conversion here)
FINAL ANSWER
-70.35 Kilojoule per Kilogram <-- Heat Rejected
(Calculation completed in 00.004 seconds)

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K J Somaiya College of Engineering (K J Somaiya), Mumbai
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11 Simple Air Cooling System Calculators

Power required to maintain pressure inside cabin excluding ram work
Go Input Power = ((Mass of Air*Specific Heat Capacity at Constant Pressure*Actual temperature of Rammed Air)/(Compressor Efficiency))*((Cabin Pressure/Pressure of Rammed Air)^((Heat Capacity Ratio-1)/Heat Capacity Ratio)-1)
Power Required to Maintain Pressure inside Cabin including Ram Work
Go Input Power = ((Mass of Air*Specific Heat Capacity at Constant Pressure*Ambient Air Temperature)/(Compressor Efficiency))*((Cabin Pressure/Atmospheric Pressure)^((Heat Capacity Ratio-1)/Heat Capacity Ratio)-1)
C.O.P. of simple air cycle
Go Actual Coefficient of Performance = (Inside temperature of cabin-Actual temperature at end of isentropic expansion)/(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air)
Mass of air to produce Q tonnes of refrigeration
Go Mass of Air = (210*Tonnage of Refrigeration in TR)/(Specific Heat Capacity at Constant Pressure*(Inside temperature of cabin-Actual temperature at end of isentropic expansion))
Expansion Work
Go Work Done per min = Mass of Air*Specific Heat Capacity at Constant Pressure*(Temperature at the end of cooling process-Actual temperature at end of isentropic expansion)
Refrigeration Effect Produced
Go Refrigeration Effect Produced = Mass of Air*Specific Heat Capacity at Constant Pressure*(Inside temperature of cabin-Actual temperature at end of isentropic expansion)
Heat rejected during cooling process
Go Heat Rejected = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Temperature at the end of cooling process)
Compression Work
Go Work Done per min = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air)
Power Required for Refrigeration System
Go Input Power = (Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air))/60
Temperature Ratio at Start and End of Ramming Process
Go Temperature Ratio = 1+(Velocity^2*(Heat Capacity Ratio-1))/(2*Heat Capacity Ratio*[R]*Initial Temperature)
COP of Air Cycle for given Input Power and Tonnage of Refrigeration
Go Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Input Power*60)

Heat rejected during cooling process Formula

Heat Rejected = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Temperature at the end of cooling process)
QR = ma*Cp*(Tt'-T4)

How does heat rejection occur during cooling process?

The compressed air is cooled by the ram air in the heat exchange. In actual practice, there is a pressure drop in the heat exchanger.

How to Calculate Heat rejected during cooling process?

Heat rejected during cooling process calculator uses Heat Rejected = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Temperature at the end of cooling process) to calculate the Heat Rejected, The Heat rejected during cooling process formula is defined as the product of the mass of air, constant pressure specific heat capacity, and difference of actual temperature at the end of isentropic compression and cooling process. Heat Rejected is denoted by QR symbol.

How to calculate Heat rejected during cooling process using this online calculator? To use this online calculator for Heat rejected during cooling process, enter Mass of Air (ma), Specific Heat Capacity at Constant Pressure (Cp), Actual End Temp of Isentropic Compression (Tt') & Temperature at the end of cooling process (T4) and hit the calculate button. Here is how the Heat rejected during cooling process calculation can be explained with given input values -> -0.07035 = 2*1005*(350-385).

FAQ

What is Heat rejected during cooling process?
The Heat rejected during cooling process formula is defined as the product of the mass of air, constant pressure specific heat capacity, and difference of actual temperature at the end of isentropic compression and cooling process and is represented as QR = ma*Cp*(Tt'-T4) or Heat Rejected = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Temperature at the end of cooling process). Mass of air is both a property of air and a measure of its resistance to acceleration when a net force is applied, Specific Heat Capacity at Constant Pressure means the amount of heat that is required to raise the temperature of a unit mass of gas by 1 degree at constant pressure, Actual End Temp of Isentropic Compression is greater than the ideal temperature & Temperature at the end of cooling process is also the temperature at which isentropic expansion starts.
How to calculate Heat rejected during cooling process?
The Heat rejected during cooling process formula is defined as the product of the mass of air, constant pressure specific heat capacity, and difference of actual temperature at the end of isentropic compression and cooling process is calculated using Heat Rejected = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Temperature at the end of cooling process). To calculate Heat rejected during cooling process, you need Mass of Air (ma), Specific Heat Capacity at Constant Pressure (Cp), Actual End Temp of Isentropic Compression (Tt') & Temperature at the end of cooling process (T4). With our tool, you need to enter the respective value for Mass of Air, Specific Heat Capacity at Constant Pressure, Actual End Temp of Isentropic Compression & Temperature at the end of cooling process and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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