Load Current using Area of X-section (1 Phase 3 Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Current Underground AC = sqrt((Line Losses*Area of Underground AC Wire)/(Resistivity*Length of Underground AC Wire*2))
I = sqrt((Ploss*A)/(ρ*L*2))
This formula uses 1 Functions, 5 Variables
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
STEP 1: Convert Input(s) to Base Unit
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
I = sqrt((Ploss*A)/(ρ*L*2)) --> sqrt((2.67*1.28)/(1.7E-05*24*2))
Evaluating ... ...
I = 64.7165766563533
STEP 3: Convert Result to Output's Unit
64.7165766563533 Ampere --> No Conversion Required
FINAL ANSWER
64.7165766563533 64.71658 Ampere <-- Current Underground AC
(Calculation completed in 00.020 seconds)

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10+ Current & Voltage Calculators

Maximum Voltage using Area of X-section (1 Phase 3 Wire US)
Go Maximum Voltage Underground AC = (2*Power Transmitted/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire))
Maximum Voltage using Volume of Conductor Material(1 Phase 3 Wire US)
Go Maximum Voltage Underground AC = sqrt(10*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*Volume Of Conductor*(cos(Phase Difference))^2))
RMS Voltage using Volume of Conductor Material(1 Phase 3 Wire US)
Go Root Mean Square Voltage = sqrt(5*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((cos(Phase Difference))^2)))
RMS Voltage using Area of X-section (1 Phase 3 Wire US)
Go Root Mean Square Voltage = (Power Transmitted/cos(Phase Difference))*sqrt(2*Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire))
Maximum Voltage using Line Losses (1 Phase 3 Wire US)
Go Maximum Voltage Underground AC = (2*Power Transmitted/cos(Phase Difference))*sqrt(Resistance Underground AC/Line Losses)
RMS Voltage using Line Losses (1 Phase 3 Wire US)
Go Root Mean Square Voltage = (Power Transmitted/cos(Phase Difference))*sqrt(2*Resistance Underground AC/(Line Losses))
Load Current using Area of X-section (1 Phase 3 Wire US)
Go Current Underground AC = sqrt((Line Losses*Area of Underground AC Wire)/(Resistivity*Length of Underground AC Wire*2))
Maximum Voltage using Load Current (1 Phase 3 Wire US)
Go Maximum Voltage Underground AC = sqrt(2)*Power Transmitted/(cos(Phase Difference)*Current Underground AC)
RMS Voltage using Load Current (1 Phase 3 Wire US)
Go Root Mean Square Voltage = sqrt(2)*Power Transmitted/(cos(Phase Difference)*Current Underground AC)
Load Current using Line Losses (1 Phase 3 Wire US)
Go Current Underground AC = sqrt(Line Losses/2*Resistance Underground AC)

Load Current using Area of X-section (1 Phase 3 Wire US) Formula

Current Underground AC = sqrt((Line Losses*Area of Underground AC Wire)/(Resistivity*Length of Underground AC Wire*2))
I = sqrt((Ploss*A)/(ρ*L*2))

Define Transmitted Power.

Transmitted Power is the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations.

How to Calculate Load Current using Area of X-section (1 Phase 3 Wire US)?

Load Current using Area of X-section (1 Phase 3 Wire US) calculator uses Current Underground AC = sqrt((Line Losses*Area of Underground AC Wire)/(Resistivity*Length of Underground AC Wire*2)) to calculate the Current Underground AC, The Load Current using Area of X-section (1 phase 3 wire US) formula is defined as the current that flows into the load of the single-phase two-wire underground system. Current Underground AC is denoted by I symbol.

How to calculate Load Current using Area of X-section (1 Phase 3 Wire US) using this online calculator? To use this online calculator for Load Current using Area of X-section (1 Phase 3 Wire US), enter Line Losses (Ploss), Area of Underground AC Wire (A), Resistivity (ρ) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Load Current using Area of X-section (1 Phase 3 Wire US) calculation can be explained with given input values -> 64.71658 = sqrt((2.67*1.28)/(1.7E-05*24*2)).

FAQ

What is Load Current using Area of X-section (1 Phase 3 Wire US)?
The Load Current using Area of X-section (1 phase 3 wire US) formula is defined as the current that flows into the load of the single-phase two-wire underground system and is represented as I = sqrt((Ploss*A)/(ρ*L*2)) or Current Underground AC = sqrt((Line Losses*Area of Underground AC Wire)/(Resistivity*Length of Underground AC Wire*2)). Line Losses is defined as the total losses occurring in an Underground AC line when in use, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Resistivity is the measure of how strongly a material opposes the flow of current through them & Length of Underground AC Wire is the total length of the wire from one end to other end.
How to calculate Load Current using Area of X-section (1 Phase 3 Wire US)?
The Load Current using Area of X-section (1 phase 3 wire US) formula is defined as the current that flows into the load of the single-phase two-wire underground system is calculated using Current Underground AC = sqrt((Line Losses*Area of Underground AC Wire)/(Resistivity*Length of Underground AC Wire*2)). To calculate Load Current using Area of X-section (1 Phase 3 Wire US), you need Line Losses (Ploss), Area of Underground AC Wire (A), Resistivity (ρ) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Line Losses, Area of Underground AC Wire, Resistivity & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Current Underground AC?
In this formula, Current Underground AC uses Line Losses, Area of Underground AC Wire, Resistivity & Length of Underground AC Wire. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Current Underground AC = sqrt(Line Losses/2*Resistance Underground AC)
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