Load Current using Constant (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Current Underground AC = sqrt(Constant Underground AC*Line Losses/(2*Resistivity*(Length of Underground AC Wire*cos(Phase Difference))^2))
I = sqrt(K*Ploss/(2*ρ*(L*cos(Φ))^2))
This formula uses 2 Functions, 6 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Constant Underground AC - Constant Underground AC is defined as the constant of line of a Overhead supply system.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
STEP 1: Convert Input(s) to Base Unit
Constant Underground AC: 0.87 --> No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
I = sqrt(K*Ploss/(2*ρ*(L*cos(Φ))^2)) --> sqrt(0.87*2.67/(2*1.7E-05*(24*cos(0.5235987755982))^2))
Evaluating ... ...
I = 12.5757508644185
STEP 3: Convert Result to Output's Unit
12.5757508644185 Ampere --> No Conversion Required
FINAL ANSWER
12.5757508644185 12.57575 Ampere <-- Current Underground AC
(Calculation completed in 00.004 seconds)

Credits

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Vishwakarma Government Engineering College (VGEC), Ahmedabad
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17 Current & Voltage Calculators

Maximum Voltage using Area of X-Section (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = sqrt((4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*Line Losses*(cos(Phase Difference))^2))
RMS Voltage using Area of X-Section (1-Phase 2-Wire US)
Go Root Mean Square Voltage = sqrt((2*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*Line Losses*((cos(Phase Difference))^2)))
Maximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = sqrt(8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*Volume Of Conductor*(cos(Phase Difference))^2))
Maximum Voltage using Line Losses (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))/cos(Phase Difference)
RMS Voltage using Line Losses (1-Phase 2-Wire US)
Go Root Mean Square Voltage = 2*Power Transmitted*sqrt(2*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))/cos(Phase Difference)
RMS Voltage using Volume of Conductor Material (1-Phase 2-Wire US)
Go Root Mean Square Voltage = sqrt(4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(cos(Phase Difference))^2*Volume Of Conductor))
Load Current using Constant (1-Phase 2-Wire US)
Go Current Underground AC = sqrt(Constant Underground AC*Line Losses/(2*Resistivity*(Length of Underground AC Wire*cos(Phase Difference))^2))
Maximum Voltage using Constant (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = sqrt(4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Constant Underground AC*Line Losses))
RMS Voltage using Constant (1-Phase 2-Wire US)
Go Root Mean Square Voltage = 2*Power Transmitted*Length of Underground AC Wire*sqrt(2*Resistivity/(Line Losses*Constant Underground AC))
RMS Voltage using Resistance (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(2*Resistance Underground AC/Line Losses)/cos(Phase Difference)
Maximum Voltage using Resistance (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(Resistance Underground AC/Line Losses)/cos(Phase Difference)
Load Current using Line Losses (1-Phase 2-Wire US)
Go Current Underground AC = sqrt(Line Losses*Area of Underground AC Wire/(2*Resistivity*Length of Underground AC Wire))
Maximum Voltage using Load Current (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = (sqrt(2))*Power Transmitted/(Current Underground AC*(cos(Phase Difference)))
Load Current (1-Phase 2-Wire US)
Go Current Underground AC = Power Transmitted*sqrt(2)/(Maximum Voltage Underground AC*cos(Phase Difference))
RMS Voltage using Load Current (1-Phase 2-Wire US)
Go Root Mean Square Voltage = Power Transmitted/(Current Underground AC*cos(Phase Difference))
Load Current using Resistance (1-Phase 2-Wire US)
Go Current Underground AC = sqrt(Line Losses/(2*Resistance Underground AC))
RMS Voltage(1-Phase 2-Wire US)
Go Root Mean Square Voltage = Maximum Voltage Underground AC/sqrt(2)

Load Current using Constant (1-Phase 2-Wire US) Formula

Current Underground AC = sqrt(Constant Underground AC*Line Losses/(2*Resistivity*(Length of Underground AC Wire*cos(Phase Difference))^2))
I = sqrt(K*Ploss/(2*ρ*(L*cos(Φ))^2))

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Load Current using Constant (1-Phase 2-Wire US)?

Load Current using Constant (1-Phase 2-Wire US) calculator uses Current Underground AC = sqrt(Constant Underground AC*Line Losses/(2*Resistivity*(Length of Underground AC Wire*cos(Phase Difference))^2)) to calculate the Current Underground AC, The Load Current using Constant (1-Phase 2-Wire US) formula is defined as the current that flows into the load of the single-phase two-wire underground system. Current Underground AC is denoted by I symbol.

How to calculate Load Current using Constant (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Load Current using Constant (1-Phase 2-Wire US), enter Constant Underground AC (K), Line Losses (Ploss), Resistivity (ρ), Length of Underground AC Wire (L) & Phase Difference (Φ) and hit the calculate button. Here is how the Load Current using Constant (1-Phase 2-Wire US) calculation can be explained with given input values -> 12.57575 = sqrt(0.87*2.67/(2*1.7E-05*(24*cos(0.5235987755982))^2)).

FAQ

What is Load Current using Constant (1-Phase 2-Wire US)?
The Load Current using Constant (1-Phase 2-Wire US) formula is defined as the current that flows into the load of the single-phase two-wire underground system and is represented as I = sqrt(K*Ploss/(2*ρ*(L*cos(Φ))^2)) or Current Underground AC = sqrt(Constant Underground AC*Line Losses/(2*Resistivity*(Length of Underground AC Wire*cos(Phase Difference))^2)). Constant Underground AC is defined as the constant of line of a Overhead supply system, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
How to calculate Load Current using Constant (1-Phase 2-Wire US)?
The Load Current using Constant (1-Phase 2-Wire US) formula is defined as the current that flows into the load of the single-phase two-wire underground system is calculated using Current Underground AC = sqrt(Constant Underground AC*Line Losses/(2*Resistivity*(Length of Underground AC Wire*cos(Phase Difference))^2)). To calculate Load Current using Constant (1-Phase 2-Wire US), you need Constant Underground AC (K), Line Losses (Ploss), Resistivity (ρ), Length of Underground AC Wire (L) & Phase Difference (Φ). With our tool, you need to enter the respective value for Constant Underground AC, Line Losses, Resistivity, Length of Underground AC Wire & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Current Underground AC?
In this formula, Current Underground AC uses Constant Underground AC, Line Losses, Resistivity, Length of Underground AC Wire & Phase Difference. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Current Underground AC = Power Transmitted*sqrt(2)/(Maximum Voltage Underground AC*cos(Phase Difference))
  • Current Underground AC = sqrt(Line Losses*Area of Underground AC Wire/(2*Resistivity*Length of Underground AC Wire))
  • Current Underground AC = sqrt(Line Losses/(2*Resistance Underground AC))
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