Load Current using Line Losses (DC Three-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Current underground DC = sqrt(Line Losses/(2*Resistance underground DC))
C1 = sqrt(Pline/(2*R1))
This formula uses 1 Functions, 3 Variables
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Current underground DC - (Measured in Ampere) - Current underground DC is defined as the current flowing through the overhead ac supply wire.
Line Losses - (Measured in Watt) - Line Losses is defined as the losses that are produced in the line.
Resistance underground DC - (Measured in Ohm) - Resistance underground DC is defined as the time rate of flow of charge through a cross-sectional area.
STEP 1: Convert Input(s) to Base Unit
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Resistance underground DC: 5 Ohm --> 5 Ohm No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
C1 = sqrt(Pline/(2*R1)) --> sqrt(0.6/(2*5))
Evaluating ... ...
C1 = 0.244948974278318
STEP 3: Convert Result to Output's Unit
0.244948974278318 Ampere --> No Conversion Required
FINAL ANSWER
0.244948974278318 0.244949 Ampere <-- Current underground DC
(Calculation completed in 00.004 seconds)

Credits

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Vishwakarma Government Engineering College (VGEC), Ahmedabad
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14 Current & Voltage Calculators

RMS Voltage using Area of X-Section (3-Phase 3-Wire US)
Go Root Mean Square Voltage = (2*Power Transmitted/cos(Theta))*sqrt(Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire))
Maximum Voltage using Area of X-Section (3-Phase 3-Wire US)
Go Maximum Voltage = (Power Transmitted/cos(Theta))*sqrt(2*Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire))
Maximum Voltage using Volume of Conductor Material (3-Phase 3-Wire US)
Go Maximum Voltage = sqrt(6*Resistivity*(Power Transmitted*Length of Wire DC)^2/(Line Losses*Volume Of Conductor*(cos(Theta))^2))
Maximum Voltage using Area of X-Section (DC Three-Wire US)
Go Maximum Voltage = sqrt(2*(Power Transmitted^2)*Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire))
Maximum Voltage using Volume of Conductor Material(DC Three-Wire US)
Go Maximum Voltage = sqrt(5*Resistivity*(Power Transmitted*Length of Wire DC)^2/(Line Losses*Volume Of Conductor))
Maximum Voltage using Load Current Per Phase (3-Phase 3-Wire US)
Go Maximum Voltage = (sqrt(6)*Power Transmitted)/(3*Current underground DC*cos(Theta))
Load Current Per Phase (3-Phase 3-Wire US)
Go Current underground DC = (sqrt(6)*Power Transmitted)/(3*Maximum Voltage*cos(Theta))
Maximum Voltage using Line Losses (DC Three-Wire US)
Go Maximum Voltage = sqrt(2*(Power Transmitted^2)*Resistance underground DC/(Line Losses))
RMS Voltage using Load Current Per Phase (3-Phase 3-Wire US)
Go Root Mean Square Voltage = Power Transmitted/(3*Current underground DC*cos(Theta))
Load Current using Line Losses (DC Three-Wire US)
Go Current underground DC = sqrt(Line Losses/(2*Resistance underground DC))
Current using Line Losses (3-Phase 3-Wire US)
Go Current underground DC = sqrt(Line Losses/(3*Resistance underground DC))
RMS Voltage Per Phase (3-Phase 3-Wire US)
Go Root Mean Square Voltage = Maximum Voltage/(sqrt(6))
Maximum Voltage using RMS Voltage Per Phase (3-Phase 3-Wire US)
Go Maximum Voltage = sqrt(6)*Root Mean Square Voltage
Maximum Voltage between Each Phase and Neutral (3-Phase 3-Wire US)
Go Maximum phase voltage = Maximum Voltage/sqrt(3)

Load Current using Line Losses (DC Three-Wire US) Formula

Current underground DC = sqrt(Line Losses/(2*Resistance underground DC))
C1 = sqrt(Pline/(2*R1))

What is the volume of conductor material in DC Three-Wire underground system?

The volume of conductor material required in this system is 1.25 times that of a 2-wire d.c.system with the one conductor earthed.

How to Calculate Load Current using Line Losses (DC Three-Wire US)?

Load Current using Line Losses (DC Three-Wire US) calculator uses Current underground DC = sqrt(Line Losses/(2*Resistance underground DC)) to calculate the Current underground DC, The Load Current using Line Losses (DC Three-Wire US) formula is defined as the current that flows into the load of the DC Three-Wire underground system. Current underground DC is denoted by C1 symbol.

How to calculate Load Current using Line Losses (DC Three-Wire US) using this online calculator? To use this online calculator for Load Current using Line Losses (DC Three-Wire US), enter Line Losses (Pline) & Resistance underground DC (R1) and hit the calculate button. Here is how the Load Current using Line Losses (DC Three-Wire US) calculation can be explained with given input values -> 0.244949 = sqrt(0.6/(2*5)).

FAQ

What is Load Current using Line Losses (DC Three-Wire US)?
The Load Current using Line Losses (DC Three-Wire US) formula is defined as the current that flows into the load of the DC Three-Wire underground system and is represented as C1 = sqrt(Pline/(2*R1)) or Current underground DC = sqrt(Line Losses/(2*Resistance underground DC)). Line Losses is defined as the losses that are produced in the line & Resistance underground DC is defined as the time rate of flow of charge through a cross-sectional area.
How to calculate Load Current using Line Losses (DC Three-Wire US)?
The Load Current using Line Losses (DC Three-Wire US) formula is defined as the current that flows into the load of the DC Three-Wire underground system is calculated using Current underground DC = sqrt(Line Losses/(2*Resistance underground DC)). To calculate Load Current using Line Losses (DC Three-Wire US), you need Line Losses (Pline) & Resistance underground DC (R1). With our tool, you need to enter the respective value for Line Losses & Resistance underground DC and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Current underground DC?
In this formula, Current underground DC uses Line Losses & Resistance underground DC. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Current underground DC = (sqrt(6)*Power Transmitted)/(3*Maximum Voltage*cos(Theta))
  • Current underground DC = sqrt(Line Losses/(3*Resistance underground DC))
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