Maximum Voltage using Area of X-Section (3-Phase 3-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Maximum Voltage = (Power Transmitted/cos(Theta))*sqrt(2*Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire))
Vm = (P/cos(θ))*sqrt(2*ρ*l/(Pline*A))
This formula uses 2 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Maximum Voltage - (Measured in Volt) - Maximum Voltage the highest voltage rating for electrical devices.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Theta - (Measured in Radian) - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Wire DC - (Measured in Meter) - Length of Wire DC is the measurement or extent of something from end to end.
Line Losses - (Measured in Watt) - Line Losses is defined as the losses that are produced in the line.
Area of underground dc wire - (Measured in Square Meter) - The Area of underground dc wire is the amount of two-dimensional space taken up by an object.
STEP 1: Convert Input(s) to Base Unit
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Wire DC: 3.2 Meter --> 3.2 Meter No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Area of underground dc wire: 0.32 Square Meter --> 0.32 Square Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Vm = (P/cos(θ))*sqrt(2*ρ*l/(Pline*A)) --> (300/cos(0.5235987755982))*sqrt(2*1.7E-05*3.2/(0.6*0.32))
Evaluating ... ...
Vm = 8.24621125123532
STEP 3: Convert Result to Output's Unit
8.24621125123532 Volt --> No Conversion Required
FINAL ANSWER
8.24621125123532 8.246211 Volt <-- Maximum Voltage
(Calculation completed in 00.004 seconds)

Credits

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Vishwakarma Government Engineering College (VGEC), Ahmedabad
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14 Current & Voltage Calculators

RMS Voltage using Area of X-Section (3-Phase 3-Wire US)
Go Root Mean Square Voltage = (2*Power Transmitted/cos(Theta))*sqrt(Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire))
Maximum Voltage using Area of X-Section (3-Phase 3-Wire US)
Go Maximum Voltage = (Power Transmitted/cos(Theta))*sqrt(2*Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire))
Maximum Voltage using Volume of Conductor Material (3-Phase 3-Wire US)
Go Maximum Voltage = sqrt(6*Resistivity*(Power Transmitted*Length of Wire DC)^2/(Line Losses*Volume Of Conductor*(cos(Theta))^2))
Maximum Voltage using Area of X-Section (DC Three-Wire US)
Go Maximum Voltage = sqrt(2*(Power Transmitted^2)*Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire))
Maximum Voltage using Volume of Conductor Material(DC Three-Wire US)
Go Maximum Voltage = sqrt(5*Resistivity*(Power Transmitted*Length of Wire DC)^2/(Line Losses*Volume Of Conductor))
Maximum Voltage using Load Current Per Phase (3-Phase 3-Wire US)
Go Maximum Voltage = (sqrt(6)*Power Transmitted)/(3*Current underground DC*cos(Theta))
Load Current Per Phase (3-Phase 3-Wire US)
Go Current underground DC = (sqrt(6)*Power Transmitted)/(3*Maximum Voltage*cos(Theta))
Maximum Voltage using Line Losses (DC Three-Wire US)
Go Maximum Voltage = sqrt(2*(Power Transmitted^2)*Resistance underground DC/(Line Losses))
RMS Voltage using Load Current Per Phase (3-Phase 3-Wire US)
Go Root Mean Square Voltage = Power Transmitted/(3*Current underground DC*cos(Theta))
Load Current using Line Losses (DC Three-Wire US)
Go Current underground DC = sqrt(Line Losses/(2*Resistance underground DC))
Current using Line Losses (3-Phase 3-Wire US)
Go Current underground DC = sqrt(Line Losses/(3*Resistance underground DC))
RMS Voltage Per Phase (3-Phase 3-Wire US)
Go Root Mean Square Voltage = Maximum Voltage/(sqrt(6))
Maximum Voltage using RMS Voltage Per Phase (3-Phase 3-Wire US)
Go Maximum Voltage = sqrt(6)*Root Mean Square Voltage
Maximum Voltage between Each Phase and Neutral (3-Phase 3-Wire US)
Go Maximum phase voltage = Maximum Voltage/sqrt(3)

Maximum Voltage using Area of X-Section (3-Phase 3-Wire US) Formula

Maximum Voltage = (Power Transmitted/cos(Theta))*sqrt(2*Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire))
Vm = (P/cos(θ))*sqrt(2*ρ*l/(Pline*A))

Why do we use 3 phase 3 wire?

The function of neutral wire in the 3 phase 3 wire system is to serve as a return wire for the general domestic supply system. The neutral is paired to each of the single-phase loads.

How to Calculate Maximum Voltage using Area of X-Section (3-Phase 3-Wire US)?

Maximum Voltage using Area of X-Section (3-Phase 3-Wire US) calculator uses Maximum Voltage = (Power Transmitted/cos(Theta))*sqrt(2*Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire)) to calculate the Maximum Voltage, The Maximum Voltage using Area of X-Section (3-phase 3-wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition. Maximum Voltage is denoted by Vm symbol.

How to calculate Maximum Voltage using Area of X-Section (3-Phase 3-Wire US) using this online calculator? To use this online calculator for Maximum Voltage using Area of X-Section (3-Phase 3-Wire US), enter Power Transmitted (P), Theta (θ), Resistivity (ρ), Length of Wire DC (l), Line Losses (Pline) & Area of underground dc wire (A) and hit the calculate button. Here is how the Maximum Voltage using Area of X-Section (3-Phase 3-Wire US) calculation can be explained with given input values -> 8.246211 = (300/cos(0.5235987755982))*sqrt(2*1.7E-05*3.2/(0.6*0.32)).

FAQ

What is Maximum Voltage using Area of X-Section (3-Phase 3-Wire US)?
The Maximum Voltage using Area of X-Section (3-phase 3-wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition and is represented as Vm = (P/cos(θ))*sqrt(2*ρ*l/(Pline*A)) or Maximum Voltage = (Power Transmitted/cos(Theta))*sqrt(2*Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire)). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Wire DC is the measurement or extent of something from end to end, Line Losses is defined as the losses that are produced in the line & The Area of underground dc wire is the amount of two-dimensional space taken up by an object.
How to calculate Maximum Voltage using Area of X-Section (3-Phase 3-Wire US)?
The Maximum Voltage using Area of X-Section (3-phase 3-wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition is calculated using Maximum Voltage = (Power Transmitted/cos(Theta))*sqrt(2*Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire)). To calculate Maximum Voltage using Area of X-Section (3-Phase 3-Wire US), you need Power Transmitted (P), Theta (θ), Resistivity (ρ), Length of Wire DC (l), Line Losses (Pline) & Area of underground dc wire (A). With our tool, you need to enter the respective value for Power Transmitted, Theta, Resistivity, Length of Wire DC, Line Losses & Area of underground dc wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Maximum Voltage?
In this formula, Maximum Voltage uses Power Transmitted, Theta, Resistivity, Length of Wire DC, Line Losses & Area of underground dc wire. We can use 6 other way(s) to calculate the same, which is/are as follows -
  • Maximum Voltage = sqrt(5*Resistivity*(Power Transmitted*Length of Wire DC)^2/(Line Losses*Volume Of Conductor))
  • Maximum Voltage = sqrt(2*(Power Transmitted^2)*Resistivity*Length of Wire DC/(Line Losses*Area of underground dc wire))
  • Maximum Voltage = sqrt(2*(Power Transmitted^2)*Resistance underground DC/(Line Losses))
  • Maximum Voltage = sqrt(6*Resistivity*(Power Transmitted*Length of Wire DC)^2/(Line Losses*Volume Of Conductor*(cos(Theta))^2))
  • Maximum Voltage = sqrt(6)*Root Mean Square Voltage
  • Maximum Voltage = (sqrt(6)*Power Transmitted)/(3*Current underground DC*cos(Theta))
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