Moment of inertia of triangle about centroidal axis x-x parallel to base Solution

STEP 0: Pre-Calculation Summary
Formula Used
Moment of Inertia about x-x axis = (Base of Triangle*Height of Triangle^3)/36
Jxx = (btri*Htri^3)/36
This formula uses 3 Variables
Variables Used
Moment of Inertia about x-x axis - (Measured in Meter⁴) - Moment of Inertia about x-x axis is defined as the quantity expressed by the body resisting angular acceleration.
Base of Triangle - (Measured in Meter) - Base of Triangle is one side in a triangle.
Height of Triangle - (Measured in Meter) - The Height of Triangle is the length of the altitude from the opposite vertex to that base.
STEP 1: Convert Input(s) to Base Unit
Base of Triangle: 2.82 Meter --> 2.82 Meter No Conversion Required
Height of Triangle: 2.43 Meter --> 2.43 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Jxx = (btri*Htri^3)/36 --> (2.82*2.43^3)/36
Evaluating ... ...
Jxx = 1.123997715
STEP 3: Convert Result to Output's Unit
1.123997715 Meter⁴ --> No Conversion Required
FINAL ANSWER
1.123997715 1.123998 Meter⁴ <-- Moment of Inertia about x-x axis
(Calculation completed in 00.004 seconds)

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7 Moment of Inertia in Solids Calculators

Moment of Inertia of Hollow Rectangle about Centroidal Axis x-x Parallel to Breadth
Go Moment of Inertia about x-x axis = ((Breadth of Rectangular Section*Length of Rectangular Section^3)-(Inner Breadth of Hollow Rectangular Section*Inner Length of Hollow Rectangle^3))/12
Moment of inertia of hollow circle about diametrical axis
Go Moment of Inertia for Solids = (pi/64)*(Outer Diameter of Hollow Circular Section^4-Inner Diameter of Hollow Circular Section^4)
Moment of inertia of rectangle about centroidal axis along x-x parallel to breadth
Go Moment of Inertia about x-x axis = Breadth of Rectangular Section*(Length of Rectangular Section^3/12)
Moment of inertia of rectangle about centroidal axis along y-y parallel to length
Go Moment of Inertia about y-y axis = Length of Rectangular Section*(Breadth of Rectangular Section^3)/12
Moment of inertia of triangle about centroidal axis x-x parallel to base
Go Moment of Inertia about x-x axis = (Base of Triangle*Height of Triangle^3)/36
Moment of inertia of semicircular section about its base
Go Moment of Inertia for Solids = 0.393*Radius of semi circle^4
Moment of inertia of semicircular section through center of gravity, parallel to base
Go Moment of Inertia for Solids = 0.11*Radius of semi circle^4

Moment of inertia of triangle about centroidal axis x-x parallel to base Formula

Moment of Inertia about x-x axis = (Base of Triangle*Height of Triangle^3)/36
Jxx = (btri*Htri^3)/36

What is moment of inertia?

Moment of inertia is defined as the quantity expressed by the body resisting angular acceleration which is the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

How to Calculate Moment of inertia of triangle about centroidal axis x-x parallel to base?

Moment of inertia of triangle about centroidal axis x-x parallel to base calculator uses Moment of Inertia about x-x axis = (Base of Triangle*Height of Triangle^3)/36 to calculate the Moment of Inertia about x-x axis, Moment of inertia of triangle about centroidal axis x-x parallel to base formula is defined as the 1/36 times of product of base of triangle and cube of the height of the triangle. Moment of Inertia about x-x axis is denoted by Jxx symbol.

How to calculate Moment of inertia of triangle about centroidal axis x-x parallel to base using this online calculator? To use this online calculator for Moment of inertia of triangle about centroidal axis x-x parallel to base, enter Base of Triangle (btri) & Height of Triangle (Htri) and hit the calculate button. Here is how the Moment of inertia of triangle about centroidal axis x-x parallel to base calculation can be explained with given input values -> 1.123998 = (2.82*2.43^3)/36.

FAQ

What is Moment of inertia of triangle about centroidal axis x-x parallel to base?
Moment of inertia of triangle about centroidal axis x-x parallel to base formula is defined as the 1/36 times of product of base of triangle and cube of the height of the triangle and is represented as Jxx = (btri*Htri^3)/36 or Moment of Inertia about x-x axis = (Base of Triangle*Height of Triangle^3)/36. Base of Triangle is one side in a triangle & The Height of Triangle is the length of the altitude from the opposite vertex to that base.
How to calculate Moment of inertia of triangle about centroidal axis x-x parallel to base?
Moment of inertia of triangle about centroidal axis x-x parallel to base formula is defined as the 1/36 times of product of base of triangle and cube of the height of the triangle is calculated using Moment of Inertia about x-x axis = (Base of Triangle*Height of Triangle^3)/36. To calculate Moment of inertia of triangle about centroidal axis x-x parallel to base, you need Base of Triangle (btri) & Height of Triangle (Htri). With our tool, you need to enter the respective value for Base of Triangle & Height of Triangle and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Moment of Inertia about x-x axis?
In this formula, Moment of Inertia about x-x axis uses Base of Triangle & Height of Triangle. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Moment of Inertia about x-x axis = Breadth of Rectangular Section*(Length of Rectangular Section^3/12)
  • Moment of Inertia about x-x axis = ((Breadth of Rectangular Section*Length of Rectangular Section^3)-(Inner Breadth of Hollow Rectangular Section*Inner Length of Hollow Rectangle^3))/12
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