Superelevation in railways Solution

STEP 0: Pre-Calculation Summary
Formula Used
Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path)
S = (G*(v^2))/([g]*r)
This formula uses 1 Constants, 4 Variables
Constants Used
[g] - Gravitational acceleration on Earth Value Taken As 9.80665
Variables Used
Superelevation - (Measured in Meter) - Superelevation is the amount of raise of outer edge with respect to the inner edge of the road surface. In case of railways the amount by which the outer rail is raised is known as superelevation.
Gauge of Track - (Measured in Meter) - Gauge of track is the distance between the rails of the track.
Velocity - (Measured in Meter per Second) - Velocity is a vector quantity (it has both magnitude and direction) and is the rate of change of the position of an object with respect to time.
Radius of Circular Path - (Measured in Meter) - Radius of circular path is measure of radius of curved road path.
STEP 1: Convert Input(s) to Base Unit
Gauge of Track: 0.2 Meter --> 0.2 Meter No Conversion Required
Velocity: 60 Meter per Second --> 60 Meter per Second No Conversion Required
Radius of Circular Path: 100 Meter --> 100 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
S = (G*(v^2))/([g]*r) --> (0.2*(60^2))/([g]*100)
Evaluating ... ...
S = 0.734195673344108
STEP 3: Convert Result to Output's Unit
0.734195673344108 Meter --> No Conversion Required
FINAL ANSWER
0.734195673344108 0.734196 Meter <-- Superelevation
(Calculation completed in 00.004 seconds)

Credits

Created by Chilvera Bhanu Teja
Institute of Aeronautical Engineering (IARE), Hyderabad
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National Institute of Technology (NIT), Tiruchirapalli
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5 Principal Parameters Calculators

Maximum velocity to avoid overturning of vehicle along level circular path
Go Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track))
Force of attraction between two masses separated by distance
Go Gravitational Force of Attraction = ([G.]*Mass of First Particle*Mass of Second Particle)/(Distance between two Masses^2)
Maximum velocity to avoid skidding away of vehicle along level circular path
Go Velocity = sqrt(Coefficient of Friction between Wheels and Ground*[g]*Radius of Circular Path)
Superelevation in railways
Go Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path)
Angle of banking
Go Angle of Banking = atan((Velocity^2)/([g]*Radius of Circular Path))

Superelevation in railways Formula

Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path)
S = (G*(v^2))/([g]*r)

What is superelevation?

In case of railways, the outer rail is raised with respect to the inner rail of the track. The amount by which the outer rail is raised is known as superelevation.

How to Calculate Superelevation in railways?

Superelevation in railways calculator uses Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path) to calculate the Superelevation, The Superelevation in railways formula is defined as the ratio of product of gauge of the track and square of the velocity of rail to the acceleration due to gravity and radius of circular path. Superelevation is denoted by S symbol.

How to calculate Superelevation in railways using this online calculator? To use this online calculator for Superelevation in railways, enter Gauge of Track (G), Velocity (v) & Radius of Circular Path (r) and hit the calculate button. Here is how the Superelevation in railways calculation can be explained with given input values -> 0.734196 = (0.2*(60^2))/([g]*100).

FAQ

What is Superelevation in railways?
The Superelevation in railways formula is defined as the ratio of product of gauge of the track and square of the velocity of rail to the acceleration due to gravity and radius of circular path and is represented as S = (G*(v^2))/([g]*r) or Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path). Gauge of track is the distance between the rails of the track, Velocity is a vector quantity (it has both magnitude and direction) and is the rate of change of the position of an object with respect to time & Radius of circular path is measure of radius of curved road path.
How to calculate Superelevation in railways?
The Superelevation in railways formula is defined as the ratio of product of gauge of the track and square of the velocity of rail to the acceleration due to gravity and radius of circular path is calculated using Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path). To calculate Superelevation in railways, you need Gauge of Track (G), Velocity (v) & Radius of Circular Path (r). With our tool, you need to enter the respective value for Gauge of Track, Velocity & Radius of Circular Path and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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