Volume of Substance 1 at Equivalence Point Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume of Solution 1 = Normality of Solution 2*(Volume of Solution 2/Normality of Solution 1)
V1 = N2*(V2/N1)
This formula uses 4 Variables
Variables Used
Volume of Solution 1 - (Measured in Cubic Meter) - The Volume of Solution 1 gives the volume of solution 1 in liters.
Normality of Solution 2 - (Measured in Mole per Cubic Meter) - The Normality of Solution 2 is described as the number of gram or mole equivalents of solution 2 present in one liter of solution 2.
Volume of Solution 2 - (Measured in Cubic Meter) - The volume of solution 2 gives the volume of the solution 2 in liters.
Normality of Solution 1 - (Measured in Mole per Cubic Meter) - The Normality of Solution 1 is described as the number of gram or mole equivalents of solution 1 present in one liter of solution 1.
STEP 1: Convert Input(s) to Base Unit
Normality of Solution 2: 0.005 Equivalents per Liter --> 5 Mole per Cubic Meter (Check conversion here)
Volume of Solution 2: 1E-05 Liter --> 1E-08 Cubic Meter (Check conversion here)
Normality of Solution 1: 7 Equivalents per Liter --> 7000 Mole per Cubic Meter (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V1 = N2*(V2/N1) --> 5*(1E-08/7000)
Evaluating ... ...
V1 = 7.14285714285714E-12
STEP 3: Convert Result to Output's Unit
7.14285714285714E-12 Cubic Meter -->7.14285714285714E-09 Liter (Check conversion here)
FINAL ANSWER
7.14285714285714E-09 โ‰ˆ 7.1E-9 Liter <-- Volume of Solution 1
(Calculation completed in 00.004 seconds)

Credits

Created by Shivam Sinha
National Institute Of Technology (NIT), Surathkal
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Verified by Akshada Kulkarni
National Institute of Information Technology (NIIT), Neemrana
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23 Number of Equivalents and Normality Calculators

Normality of substance 1 at Equivalence point
Go Normality of Solution 1 = Normality of Solution 2*(Volume of Solution 2/Volume of Solution 1)
Normality of substance 2 at Equivalence point
Go Normality of Solution 2 = Normality of Solution 1*(Volume of Solution 1/Volume of Solution 2)
Volume of Substance 1 at Equivalence Point
Go Volume of Solution 1 = Normality of Solution 2*(Volume of Solution 2/Normality of Solution 1)
Volume of substance 2 at equivalence point
Go Volume of Solution 2 = Normality of Solution 1*(Volume of Solution 1/Normality of Solution 2)
Equivalent Mass given Molality and Normality
Go Equivalent Weight = Molarity*(Molar Mass/Normality)
Normality given Molality and Equivalent Mass
Go Normality = Molarity*(Molar Mass/Equivalent Weight)
Number of Moles of Solute given Number of Equivalents of Solute
Go Number of Moles of Solute = Number of Equivalents/N Factor
Number of Equivalents of Solute using Valency Factor
Go Number of Equivalents = Number of Moles of Solute*N Factor
Valency Factor given Number of Equivalents of Solute
Go N Factor = Number of Equivalents/Number of Moles of Solute
Number of Equivalents of Solute
Go Number of Equivalents = Mass of Solute/Equivalent Weight
Number of Equivalents of Solute given Normality
Go Number of Equivalents = Normality*Volume of Solution
Volume of Solution given Normality
Go Volume of Solution = Number of Equivalents/Normality
Normality
Go Normality = Equivalent of Solute/Liters of Solution
Number of Equivalents given Molarity and Normality
Go Number of Equivalents = Normality/Molarity
Normality given Molarity and Number of Equivalents
Go Normality = Molarity*Number of Equivalents
Normality given Molarity and Valency Factor
Go Normality = Molarity*N Factor
Valency Factor using Molarity and Normality
Go N Factor = Normality/Molarity
Basicity given Molarity and Normality
Go Basicity = Normality/Molarity
Normality given Molarity and Basicity
Go Normality = Molarity*Basicity
Acidity given Molarity and Normality
Go Acidity = Normality/Molarity
Normality given Molarity and Acidity
Go Normality = Molarity*Acidity
Normality using Volume Strength of Hydrogen Peroxide
Go Normality = Volume Strength/5.6
Volume Strength using Normality
Go Volume Strength = 5.6*Normality

Volume of Substance 1 at Equivalence Point Formula

Volume of Solution 1 = Normality of Solution 2*(Volume of Solution 2/Normality of Solution 1)
V1 = N2*(V2/N1)

What is normality?

Normality is described as the number of gram or mole equivalents of solute present in one liter of a solution. When we say equivalent, it is the number of moles of reactive units in a compound. Normality in chemistry is one of the expressions used to measure the concentration of a solution. It is abbreviated as โ€˜Nโ€™ and is sometimes referred to as the equivalent concentration of a solution. It is mainly used as a measure of reactive species in a solution and during titration reactions or particularly in situations involving acid-base chemistry.

What is equivalence point?

The equivalence point, or stoichiometric point, of a chemical reaction, is the point at which chemically equivalent quantities of reactants have been mixed. In other words, the moles of acid are equivalent to the moles of the base, according to the equation (this does not necessarily imply a 1:1 molar ratio of acid: base, merely that the ratio is the same as in the equation). It can be found by means of an indicator, for example, phenolphthalein or methyl orange.

How to Calculate Volume of Substance 1 at Equivalence Point?

Volume of Substance 1 at Equivalence Point calculator uses Volume of Solution 1 = Normality of Solution 2*(Volume of Solution 2/Normality of Solution 1) to calculate the Volume of Solution 1, The Volume of substance 1 at equivalence point formula is defined as the product of the volume of substance 2 and the ratio of the normality of substance 2 to the normality of substance 1. Volume of Solution 1 is denoted by V1 symbol.

How to calculate Volume of Substance 1 at Equivalence Point using this online calculator? To use this online calculator for Volume of Substance 1 at Equivalence Point, enter Normality of Solution 2 (N2), Volume of Solution 2 (V2) & Normality of Solution 1 (N1) and hit the calculate button. Here is how the Volume of Substance 1 at Equivalence Point calculation can be explained with given input values -> 7.1E-6 = 5*(1E-08/7000).

FAQ

What is Volume of Substance 1 at Equivalence Point?
The Volume of substance 1 at equivalence point formula is defined as the product of the volume of substance 2 and the ratio of the normality of substance 2 to the normality of substance 1 and is represented as V1 = N2*(V2/N1) or Volume of Solution 1 = Normality of Solution 2*(Volume of Solution 2/Normality of Solution 1). The Normality of Solution 2 is described as the number of gram or mole equivalents of solution 2 present in one liter of solution 2, The volume of solution 2 gives the volume of the solution 2 in liters & The Normality of Solution 1 is described as the number of gram or mole equivalents of solution 1 present in one liter of solution 1.
How to calculate Volume of Substance 1 at Equivalence Point?
The Volume of substance 1 at equivalence point formula is defined as the product of the volume of substance 2 and the ratio of the normality of substance 2 to the normality of substance 1 is calculated using Volume of Solution 1 = Normality of Solution 2*(Volume of Solution 2/Normality of Solution 1). To calculate Volume of Substance 1 at Equivalence Point, you need Normality of Solution 2 (N2), Volume of Solution 2 (V2) & Normality of Solution 1 (N1). With our tool, you need to enter the respective value for Normality of Solution 2, Volume of Solution 2 & Normality of Solution 1 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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